How can I populate my C# object with the JSON object passed via AJAX? This is the JSON object passed to a C# web method from the page using JSON.stringify: { "user": { "n...
Of course, the correct MIME media type for JSON is application/json, but it's necessary to realize what type of data is expected in your application. For example, I use Java Ext GWT and the server response must go as text/html but contains JSON data.
Yes. The JSON format has a lot of dead-space between elements and is space-insensitive in those regions, so there's no reason why you can't have single or multi-line comments there. Many parsers and minifiers support JSON comments as well, so just make sure your parser supports them.
json dump will write the json as string in the file. How can I get a json file that is not in the form of string, but just dictionary-like? Is it possible?
354 A JSON string must be double-quoted, according to the specs, so you don't need to escape '. If you have to use special character in your JSON string, you can escape it using \ character. See this list of special character used in JSON :
Ex: I had one JSON object on each line, without being wrapped in an array, and it formatted the first line's object, and deleted the other 2. Undo-ing and wrapping in the array, fixed it, but just something to keep in mind.
If you are reading the data from the Internet instead, the same techniques can generally be used with the response you get from your HTTP API (it will be a file-like object); however, it is heavily recommended to use the third-party Requests library instead, which includes built-in support for JSON requests.
I did it many times, and each time I forgot where it was. Menu File → Preferences → Settings. I get this: I want to open file settings.json (editable JSON file) instead. How can I do that?
The launch.json file should be inside the .vscode folder, but it is not present there. How can I get this file so that I can modify the configurations?
I am new to Python and I am playing with JSON data. I would like to dynamically build a JSON object by adding some key-value to an existing JSON object. I tried the following but I get TypeError: ...
